Con hno3 is 69% by wight hno3 and has a density of 1.41gm/ml at 20`c.what volume and wght of conc hno3 acid are needed to prepare 100ml of 6M acid?

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Vikas TU · Answer

To prepare 100ml of 6M acid => moles would be = > 6 x 100/1000 = > 0.6 And 69% by weight, Volume = mass/density => 69/1.41 = > 48.936 ml moles => 0.6 = weight/63 Weight = 378/10 = > 37.8 gms.

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Con hno3 is 69% by wight hno3 and has a density of 1.41gm/ml at 20`c.what volume and wght of conc hno3 acid are needed to prepare 100ml of 6M acid?

Con hno3 is 69% by wight hno3 and has a density of 1.41gm/ml at 20`c.what volume and wght of conc hno3 acid are needed to prepare 100ml of 6M acid?

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Con hno3 is 69% by wight hno3 and has a density of 1.41gm/ml at 20`c.what volume and wght of conc hno3 acid are needed to prepare 100ml of 6M acid?

Con hno3 is 69% by wight hno3 and has a density of 1.41gm/ml at 20`c.what volume and wght of conc hno3 acid are needed to prepare 100ml of 6M acid?

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