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Caluculate the volume at NTP occupied by 6.25g of nitrogen
First Calculate the number of moles of Nitrogen,n = 6.25/28 At NTP,V = n*22.4put the n value and get the volume in litre.
no. of mole of 6.25g nitrogen =6.25/28 [equation 1]at ntp conditionno. of mole=V/22.4 [equation 2]by equation 1 and 2V/22.4=6.25/28V=6.25/28×22.4V=5ans V=5lit
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