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Grade 12th passPhysical Chemistry

calculate the two longest wavelength of the raditions emitted when hydrogen atoms makes transitions from higher state to n=2 state

pracheta

8 Years agoGrade 12th pass

1 Answer

Eshan

8 Years ago

Dear student,

The two longest wavelengths would be for transitions corresponding to least energy. Hence the two wavelengths correspond to transitions $3\rightarrow 2$ and $4\rightarrow 2$ .

Hence $\dfrac{hc}{\lambda_1}=13.6eV(\dfrac{1}{2^2}-\dfrac{1}{3^2})=1.88eV$

and $\dfrac{hc}{\lambda_2}=13.6eV(\dfrac{1}{2^2}-\dfrac{1}{4^2})=2.55eV$

$\implies \lambda_1=659.5nm$ , $\implies \lambda_2=486.3nm$

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