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        calculate the osmotic pressure of 1% of kcl solution which dissociate to an extent of 80%
one year ago

Arun
22795 Points
							Dear Vikash KCl ------>  K +  Cl1 - @.        @ .    @ i = 1 - @ +@ +@ = 1 + @ = 1 + 0.8 = 1.8 C = 1000/( 74.5* 100) = 0.34 T = 273 + 27 = 300 K (there is no temp given in question I have assumed temp as 27°c) Now $\pi$ = i C RT = 1.8 * 0.34 * 0.0821 * 300   = 5.98 atm  RegardsArun (askIITians forum expert)

one year ago
763 Points
							Dear vikash,osmotic pressure = i.C.R.T where i= vant hoff factor , c is conc. , R is gas constant and T is temp.now in your question temperature is not given and data is insufficient to find the concentration , if you have all data then you can calculate osmotic pressure by using above expression..Thanks and Regards Adarsh

one year ago
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