Grade 12Physical Chemistry
calculate the osmotic pressure of 1% of kcl solution which dissociate to an extent of 80%
2 Answers
Arun
Dear Vikash
KCl ------> K + Cl
1 - @. @ . @
i = 1 - @ +@ +@ = 1 + @ = 1 + 0.8 = 1.8
C = 1000/( 74.5* 100)
= 0.34
T = 273 + 27 = 300 K (there is no temp given in question I have assumed temp as 27°c)
Now
= 5.98 atm
Regards
Arun (askIITians forum expert)
Adarsh
Dear vikash,
osmotic pressure = i.C.R.T where i= vant hoff factor , c is conc. , R is gas constant and T is temp.
now in your question temperature is not given and data is insufficient to find the concentration , if you have all data then you can calculate osmotic pressure by using above expression..
Thanks and Regards
Adarsh
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