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`        Calculate the numbers of electron in 18 ml of water at 4 degree celsius and 1 atm pressure `
8 months ago

Arun
23338 Points
```							We know density of water is 1 gm/cc or 1 gm/ml. So 18 ml of water contains 18 gm of water implies 1 mole of water.By Avogadro no. 1 mole of water contains 6.023 x 10^(23) molecules of water.But each molecule of water contains 10 electrons.Thus 6.023 x 10^(23) molecules of water will contain 10 x 6.023 x 10^(23) electrons= 6.023 x 10^(24) electrons
```
8 months ago
Khimraj
3008 Points
```							Given, volume of water = 18ml and density of water at 4°C = 1g/ml so, mass of water = 18 × 1 = 18g Mole of water = mass/molar mass = 18g/18g/mol = 1 mol ∴ number of water molecule = mole of water × Avogadro's number= 1 × 6.023 × 10²³= 6.023 × 10²³We know, there are 10 electrons in a molecule of water .e.g., 8 electrons of Oxygen atom and 2 electrons of each two hydrogen atoms.Now, number of electrons = number of water molecule × 10= 6.023 × 10²³ × 10 = 6.023 × 10²⁴
```
8 months ago
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• Mind Map
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• NCERT Solutions
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