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Grade 12th passPhysical Chemistry

calculate the number of molecules of oxalic acid in 100ml of 0.2 normality oxalic acid solution

Profile image of Vishal YaDaV
8 Years agoGrade 12th pass
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1 Answer

Profile image of swetan
8 Years ago
As oxalic acid is dibasic in nature,n-factor (bascity)=2Now,Normality=No .of moles/n-factor/volume in litres so,0.02=n×2÷0.1 I. e. n=0.001 thus no.of molecules=avagafro no/no.of moles= 6.022×10^20