Calculate the mass percentage of benzene (C6H6) and carbon tetrachloride (CCl4) if 22 g of benzene is dissolved in 122 g of carbon tetrachloride.

Mass of the total mixture= 22g(benzene) + 122g(CCL4)=144g

Mass % of benzene=(Mass of benzene/Mass of the total mixture)*100
=(22g/144g)*100
=15.28%
Similarly, Mass % of CCL4=(Mass of CCL4/Mass of the total mixture)*100
=(122g/144g)*100
=84.72%

In general, Mass% of any component(X) in a mixture
=(Mass of component(X)/mass of total mixture)*100