Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
calculate kinetic energy of ejected electron when uv-radiations of frequency 1.6*10^15 strikes the surface of potassium metal .threshold frequency is 5*10^14
Frequency of uv light, fy = 1.6×10^15 HzThreshold frequency of Potassium, f0 = 5×10^14 HzSince the frequency (and hence energy) of the incident light is more than the threshold frequency, electron will be emitted from its surface. The amount of energy which will be used to remove the electron is called work function, given by (h×f0)The rest amount of energy of the incident light will be used to provide kinetic energy to the emitted electron.So KE of electron = energy of incident light - work function of potassiumOr KE = h(fy) - h(f0)Or KE = h×( fy- f0)Or KE = 6.63×10^(-34) × (1.6×10^15 - 5×10^14) Or KE = 6.63×10^(-20) × 11Or KE = 6.793 × 10^(-19) JKE of emitted electron is 6.793 × 10^(-19) J
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -