MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        (c) 4NH3 + SO2 ? 4NO2 + 6H2O

The equality in this case is

-1/4 d[NH3]/dt = -1/5 d[O2]/dt = 1/4 d[NO2]/dt = 1/6 d[H2O]/dt

So -d[NH3 ]/dt = -4/3 d[O2]/dt = d[NO2 ]/dt = d[H2O]/dt


is there any correction required
4 years ago

Answers : (1)

Aarti Gupta
askIITians Faculty
300 Points
							Yes the equality for the above equation will be the same.
Thanks & Regards
Aarti Gupta
askiitians Faculty
4 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 1,590 off

COUPON CODE: SELF10


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 276 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details