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```
(c) 4NH3 + SO2 ? 4NO2 + 6H2O The equality in this case is -1/4 d[NH3]/dt = -1/5 d[O2]/dt = 1/4 d[NO2]/dt = 1/6 d[H2O]/dt So -d[NH3 ]/dt = -4/3 d[O2]/dt = d[NO2 ]/dt = d[H2O]/dt is there any correction required

```
6 years ago

Aarti Gupta
300 Points
```							Yes the equality for the above equation will be the same.Thanks & RegardsAarti Guptaaskiitians Faculty
```
6 years ago
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• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions