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Grade: 12th pass
`        Bromine monochloride, BrCl decomposes into bromine and chlorine and reaches the equilibrium: 2BrCl (g) = Br2 (g) + Cl2 (g) for which Kc= 32 at 500 K. If initially pure BrCl is present at a concentration of 3.30 mbar, what is its partial pressure in the mixture at equilibrium`
3 years ago

## Answers : (1)

Vikas TU
9756 Points
```							Already ANswered this:Plz check your previous question,             2BrCl (g) = Br2 (g) + Cl2 (g) t=0            3.3 * 10^-3    0              0t=t           3.3 * 10^-3 – x   x/2            x/2Kc = x^2/4(3.3 * 10^-3 – x)^2 = 32x/(3.3 * 10^-3 – x) = 2 x 4 x root(2)x =  37.3 –  11.3x12.3x = 37.3x = 3.035 mBar.At eqm. initial partial pressure would be hence,x/2 for each Br2 and Cl2 that is = > 1.517 mBar.
```
3 years ago
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