Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
At 100 C and 1 atm, density of a liquid water is 1 g/cc and that of water vapour is 0.0006 g/cc. Then the volume occupied by water molecules in 1 L steam at that temperature is how much? At 100 C and 1 atm, density of a liquid water is 1 g/cc and that of water vapour is 0.0006 g/cc. Then the volume occupied by water molecules in 1 L steam at that temperature is how much?
Dear stdeunt,We have the density of liquid water and water vapour respectively as:1 kg/l and 0.0006 kg/l.Hence the mass of water in 1 l of steam would be 0.0006 kg.Thus, the required volume would be given by:0.0006/1=0.0006 litres.RegardsSumit
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -