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Grade: 12
        
An element cystalises in fcc and has edge length 0.56nm. Calculate the density of the element. Molar mass of the element is 40 gmol-1
6 months ago

Answers : (1)

Arun
20876 Points
							

The density of the crystal is given by the formula:

d = ZM/a^3NA

Given data Z for FCC = 4; M (atomic mass) = 40 g/mol; a (inter-atomic distance) = 0.556 nm or 0.556x10^-9 m, Substituting the values in the formula the density would be

 d = (4*40 g)/(0.556x10^-9m)^3*6.023x10^23

  = 160/(0.1719x10^-27m3) *6.023x10^23

  = 1.546x10^6 g/m3

  d = 1.546 g/cm3

6 months ago
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