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`        An element cystalises in fcc and has edge length 0.56nm. Calculate the density of the element. Molar mass of the element is 40 gmol-1`
10 months ago

Arun
22552 Points
```							The density of the crystal is given by the formula:d = ZM/a^3NAGiven data Z for FCC = 4; M (atomic mass) = 40 g/mol; a (inter-atomic distance) = 0.556 nm or 0.556x10^-9 m, Substituting the values in the formula the density would be d = (4*40 g)/(0.556x10^-9m)^3*6.023x10^23  = 160/(0.1719x10^-27m3) *6.023x10^23  = 1.546x10^6 g/m3  d = 1.546 g/cm3
```
10 months ago
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