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An element crystallizes in fcc lattice having edge length 400 pm. Calculate the maximum diameter of atom which can be placed in interstitial site without distorting the structure.

An element crystallizes in fcc lattice having edge length 400 pm. Calculate the maximum diameter of atom which can be placed in interstitial site without distorting the structure.

Grade:11

2 Answers

Sakshi
askIITians Faculty 652 Points
8 years ago
For an fcc, if one says that the \sqrt{2 } a = 4r

thus, r = a/2 \sqrt{2 }
Thus, the maximum diameter of the atom to be occupied in the interstitial site is a/ \sqrt{2 }
Yeshwanth Talwar
37 Points
6 years ago
Either octahedral voids –r 0.414r ⎛ ⎞ ⎜ ⎟ ⎝ ⎠ or tetrahedral voids –r 0.225r ⎛ ⎞ ⎜ ⎟ ⎝ ⎠ are occupied by interstitial sites inFCC where r+ is the radius of atom in interstitial sites and r– is the radius of atom forming the cubic lattice.Diameter of interstitial site = 117.1 = 2 0.414 24 a a = 400 pm

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