An electron in a hydrogen atom in its ground state absorbs energy equal to the ionisation energy of Li+2 the wavelength of emitted electron is

Question

Khimraj · Answer

Ionization energy for Li2+= 13.6 Z²/n² eV
Z=3. Thus, I.E= 122.4 eV.
Energy needed to eject electron from H in ground state=13.6 eV.
Kinetic energy of electron= Energy supplied-Energy required.
=> 122.4eV -13.6 eV.= 108.8 eV.
Now use De Broglie equation,

wavelength = hc/E

= 6.63*10^-34*3*10⁸/108.8*1.6*10^-19 = 114.2 A^o

Hope it clears.

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An electron in a hydrogen atom in its ground state absorbs energy equal to the ionisation energy of Li+2 the wavelength of emitted electron is

An electron in a hydrogen atom in its ground state absorbs energy equal to the ionisation energy of Li+2 the wavelength of emitted electron is

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An electron in a hydrogen atom in its ground state absorbs energy equal to the ionisation energy of Li+2 the wavelength of emitted electron is

An electron in a hydrogen atom in its ground state absorbs energy equal to the ionisation energy of Li+2 the wavelength of emitted electron is

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