AgCl has the same structure as that of NaCl .The edge length of unit cell of AgCl is found to be 555pm and the density of AgCl is 5.561g cm ^-3.find the percentage of site that are unoccupied

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Arun · Answer

density of a crystal is mass/volumehere mass increases due to filling of impurity thus density increasespercentage of site that are unoccupiedno of agcl atom in unit cell=4density=5.561g/cm^3volume of unit cell=17*10^-23percentage unoccupied=100-percentage occupied=100-{(4*143.5/Na)/5.561}/17*10^-23= 0.24% RegardsArun(askIITians forum expert)

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AgCl has the same structure as that of NaCl .The edge length of unit cell of AgCl is found to be 555pm and the density of AgCl is 5.561g cm ^-3.find the percentage of site that are unoccupied

AgCl has the same structure as that of NaCl .The edge length of unit cell of AgCl is found to be 555pm and the density of AgCl is 5.561g cm ^-3.find the percentage of site that are unoccupied

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AgCl has the same structure as that of NaCl .The edge length of unit cell of AgCl is found to be 555pm and the density of AgCl is 5.561g cm ^-3.find the percentage of site that are unoccupied

AgCl has the same structure as that of NaCl .The edge length of unit cell of AgCl is found to be 555pm and the density of AgCl is 5.561g cm ^-3.find the percentage of site that are unoccupied

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