A uniformly accelerated body travels 100m during the 7th second and 110m in the 9th second of its motion. If it is a case of uniform acceleration determine the acceleration and initial velocity. Also calculate the distance traveled by the body during the 11th second of its motion.

Question

Saurabh Koranglekar · Answer

Aryan · Answer

Hello Dear, questions like these seem tiring and frustrating but in the end it sums up to your basics. let's start from the 1 st step, As uniform acceleration and distance travelled in nth speed is asked ; DŃ= u+a/2 (2n-1) . substitute accordingly . 100=u + a/2{2(7)-1}. & 110=u+a/2{2(9)-1}. Using the simultaneous eqns, 10=1/2a(17-13) . so ur acceleration would be around 5ms^-2. Similarly substitute value of acceleration in any of the 2 given equations of distance (u+a/2 {2(n)-1} to get value of u as 67.5m/s.. Find distance travelled in 11 th sec, Dn = 67.5+5/2(2*11-1) = 120m .i hope I mcorrect :)

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A uniformly accelerated body travels 100m during the 7th second and 110m in the 9th second of its motion. If it is a case of uniform acceleration determine the acceleration and initial velocity. Also calculate the distance traveled by the body during the 11th second of its motion.

A uniformly accelerated body travels 100m during the 7th second and 110m in the 9th second of its motion. If it is a case of uniform acceleration determine the acceleration and initial velocity. Also calculate the distance traveled by the body during the 11th second of its motion.

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A uniformly accelerated body travels 100m during the 7th second and 110m in the 9th second of its motion. If it is a case of uniform acceleration determine the acceleration and initial velocity. Also calculate the distance traveled by the body during the 11th second of its motion.

A uniformly accelerated body travels 100m during the 7th second and 110m in the 9th second of its motion. If it is a case of uniform acceleration determine the acceleration and initial velocity. Also calculate the distance traveled by the body during the 11th second of its motion.

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