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`        a solution is obtained by mixing 300g of 25% solution and 400g of 40% solution by mass .calculate the mass% of the resulting mixture`
11 months ago

```							Dear studentAccording to question,300g of 25% solution contains solute = (300 x 25) / 100 = 75g&400g of 40% solution contains solute = (400 x 40) / 100 = 160gTotal solute = 75 + 160 = 235gAs given in the question, total solution =300 + 400 = 700gPercentage of solute in the final solution = (235 x100) / 700 = 33.5%Percentage of water in the final solution = 100 - 33.5 = 65.5%
```
11 months ago
```							Mass% =(mass of one component/total mass of solution)×100Acc. Ques:In 25% solution, mass of solute=( 25×300)\100=75 gMass of solvent=300-75=225gSimilarly,In 40% solution, Mass of solute= 40×400)100= 160g Mass of solvent=240gTherefore, total solute=235gTotal solvent=465gMass%=(235/465)*100=50.53%
```
11 months ago
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