A mixture of FeO and Fe3O4 when heated in the air to constant weight gain 5% in its weight. What is the percentage of Fe3O4 in the mixture?

Question

Vikas TU · Answer

Let x and y be their molar masses respectively, Hence the percentage of Fe3O4 = y*100/1.05*(x+y) we know x = 72g and y = 231.5g On putting the values we get, => 231.5*100/1.05*(231.5+72) = 73 %

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A mixture of FeO and Fe3O4 when heated in the air to constant weight gain 5% in its weight. What is the percentage of Fe3O4 in the mixture?

A mixture of FeO and Fe3O4 when heated in the air to constant weight gain 5% in its weight. What is the percentage of Fe3O4 in the mixture?

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A mixture of FeO and Fe3O4 when heated in the air to constant weight gain 5% in its weight. What is the percentage of Fe3O4 in the mixture?

A mixture of FeO and Fe3O4 when heated in the air to constant weight gain 5% in its weight. What is the percentage of Fe3O4 in the mixture?

1 Answers

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