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Grade: 12
        A mixture of FeO and Fe3O4 when heated in the air to constant weight gain 5% in its weight. What is the percentage of Fe3O4 in the mixture?
3 years ago

Answers : (1)

Vikas TU
11138 Points
							
Let x and y be their molar masses respectively,
Hence the percentage of Fe3O4 = y*100/1.05*(x+y)
we know x  = 72g and y = 231.5g
On putting the values we get,
=> 231.5*100/1.05*(231.5+72) = 73 %
3 years ago
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