A compound is made up of A and B. A is placed on corner and face centre and B is placed on body centre and edge centre. What will be formula if all atoms on one body diagonal plane is removed???
How to do it??

Question

Khimraj · Answer

initial no of atom A = 8*1/8 + 6*1/2 = 4 B = 1*1 + 12*1/4 = 4 no of atom on one body diagonal A = 2*1/8 = ¼ B = 1*1 = 1 remaining atom A = 4 – ¼ = 15/4 B = 4 -1 = 4 so formula is A 15/4 B 4 = A 15 B 16 Hope it clears.

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A compound is made up of A and B. A is placed on corner and face centre and B is placed on body centre and edge centre. What will be formula if all atoms on one body diagonal plane is removed??? How to do it??

A compound is made up of A and B. A is placed on corner and face centre and B is placed on body centre and edge centre. What will be formula if all atoms on one body diagonal plane is removed???
How to do it??

1 Answers

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A compound is made up of A and B. A is placed on corner and face centre and B is placed on body centre and edge centre. What will be formula if all atoms on one body diagonal plane is removed??? How to do it??

A compound is made up of A and B. A is placed on corner and face centre and B is placed on body centre and edge centre. What will be formula if all atoms on one body diagonal plane is removed???How to do it??

1 Answers

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Other Related Questions on Physical Chemistry

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A compound is made up of A and B. A is placed on corner and face centre and B is placed on body centre and edge centre. What will be formula if all atoms on one body diagonal plane is removed???
How to do it??