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Grade: 11

                        

A balloon having 8gm Ne gas and radius 20 cm is pricked and 7gm of Ne gas effused from it. What will be the radius of the balloon under similar condition

3 years ago

Answers : (2)

Himanshu Angane
15 Points
							
Hi friend 
PV=nRT
For neon
P×4/3×3.14×20^3=8/20×R×T
You'll get
83733=RT/P
After effused 7 gram reaming 1 gram
PV=nRT
PC=1/20×RT
20V=RT/P
FROM ABOVE 
20V=83733
V=83733/20
V=4186
Now 
R^3=4168×3/3.14×4
R^3=1000
R=10cm
Is the answer
 
83733=after effused 7 gram
 
one year ago
shethsaumya03
7 Points
							
PV = nRT
one year ago
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