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A 500g solid cube haivng an edge of length 20 cm floats in water.how much volume of the cube is outside the water?Density of water is 1000kg/m^3?
Suppose h be the height of cubical block above the water.Volume of cubical block = 20 x 20 x 20 = 8x10^3 cm^3 = 8x10^3x 10^-6 m^3 = 8x10^-3 m^3mass of cubical block = 500 g = 500x10^-3 = 0.5 kgvolume of water displaced by cubical block = 20x10^-2x20x10^-2x(20x10^-2 - h)= 400x(20x10^-2-h)x10^-4 m^3Mass of water displaced = 400x(20x10^-2 - h ) x10^-4 x 1000 = 40x(20x10^-2-h) kgby law of floatation Mass of water displaced = mass of cubical block 40x(20x10^-2-h) = 0.5 h = 0.075 mh = 7.5 cmHence the volume above the water = 20x20x7.5 = 3000cm^3Thanks & Regards,Nirmal SinghAskiitians faculty
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