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50g of caco3 is allowed to react with 73.5g of h3po4 calculate 1 amount of ca3(po4)2 formed in moles and 2. Amount of unreacted reagents in moled

50g of caco3 is allowed to react with 73.5g of h3po4 calculate 1 amount of ca3(po4)2 formed in moles and 2. Amount of unreacted reagents in moled

Grade:11

1 Answers

Arun
25750 Points
5 years ago
Dear Nancy
 
 
in my point of veiw,
balanced equation- 3CaCo3+2H2Po4 gives Ca3(Po4)2+3Co2+3H2O  so
210g of CaCo3 and 196 H3Po4 gives 310g of Ca3(Po4)
According to problem,
50gof CaCo3 and 73.5 gH3Po4 gives x g of  Ca3(pO4) then ‘
x=(50+73.5)*310/210+196
i.e. equal to 75.66205g
 
 
Regards
Arun

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