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Grade: 11
        
4g of M2ox oxide was reduced to 2.8g of metal. If atomic mass of metal is 56g the number of O-atom in oxide is
 
one year ago

Answers : (1)

Vikas TU
6874 Points
							
From mole concept 2 we get,
Moles of M * x = Moles of M* x
Hence,
moles of M = 4*2/(2*56 + 16x)
that is equals to => 2.8 / 56
Therefore,
8/(16x + 112) = 1/20
160 = 16x + 112
16x  = 58
x = 58/16
Moles of O atoms => 4/(112 + 16*58/16)*58/16 
No. of atoms = > 0.0852 * 6.023 x 10^23 atoms = > 0.513 x 10^23 atoms.
one year ago
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