Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        4g of M2ox oxide was reduced to 2.8g of metal. If atomic mass of metal is 56g the number of O-atom in oxide is `
2 years ago

Vikas TU
8378 Points
```							From mole concept 2 we get,Moles of M * x = Moles of M* xHence,moles of M = 4*2/(2*56 + 16x)that is equals to => 2.8 / 56Therefore,8/(16x + 112) = 1/20160 = 16x + 11216x  = 58x = 58/16Moles of O atoms => 4/(112 + 16*58/16)*58/16 No. of atoms = > 0.0852 * 6.023 x 10^23 atoms = > 0.513 x 10^23 atoms.
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Physical Chemistry

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions