MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12

                        

200 ml 0.1 molar H 2 SO 4 reacts with 500 ml 0.1 molar NaOH.Density of solution is 1.4g/ml.Calculate molality of left specie.

5 years ago

Answers : (1)

Pankaj
askIITians Faculty
131 Points
							H2SO4 + NaOH → H2O + Na2SO4
200 mL 0.1 M H2SO4 solution = 0.02 mole H2SO4
500 mL 0.1 M NaOH solution = 0.05 mole NaOH
From the equation 1 mole H2SO4 reacts with 1 mole NaOH
So, 0.02 mole H2SO4 will react only with 0.02 mole NaOH and 0.03 mole NaOH will left unreacted.
0.03 mole in 500 ml = 0.06 molar solution
Mass of solvent = 500 ml x 1.4 = 700 g = 0.7 kg
Molality = 0.03/0.7 = 0.0428
5 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details