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200 ml 0.1 molar H 2 SO 4 reacts with 500 ml 0.1 molar NaOH.Density of solution is 1.4g/ml.Calculate molality of left specie.

200 ml 0.1 molar H2SO4 reacts with 500 ml 0.1 molar NaOH.Density of solution is 1.4g/ml.Calculate molality of left specie.

Grade:12

1 Answers

Pankaj
askIITians Faculty 131 Points
8 years ago
H2SO4 + NaOH → H2O + Na2SO4
200 mL 0.1 M H2SO4 solution = 0.02 mole H2SO4
500 mL 0.1 M NaOH solution = 0.05 mole NaOH
From the equation 1 mole H2SO4 reacts with 1 mole NaOH
So, 0.02 mole H2SO4 will react only with 0.02 mole NaOH and 0.03 mole NaOH will left unreacted.
0.03 mole in 500 ml = 0.06 molar solution
Mass of solvent = 500 ml x 1.4 = 700 g = 0.7 kg
Molality = 0.03/0.7 = 0.0428

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