200 ml 0.1 molar H 2 SO 4 reacts with 500 ml 0.1 molar NaOH.Density of solution is 1.4g/ml.Calculate molality of left specie.

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Pankaj · Answer

H 2 SO 4 + NaOH &rarr; H 2 O + Na 2 SO 4 200 mL 0.1 M H 2 SO 4 solution = 0.02 mole H 2 SO 4 500 mL 0.1 M NaOH solution = 0.05 mole NaOH From the equation 1 mole H 2 SO 4 reacts with 1 mole NaOH So, 0.02 mole H 2 SO 4 will react only with 0.02 mole NaOH and 0.03 mole NaOH will left unreacted. 0.03 mole in 500 ml = 0.06 molar solution Mass of solvent = 500 ml x 1.4 = 700 g = 0.7 kg Molality = 0.03/0.7 = 0.0428

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200 ml 0.1 molar H 2 SO 4 reacts with 500 ml 0.1 molar NaOH.Density of solution is 1.4g/ml.Calculate molality of left specie.

200 ml 0.1 molar H₂SO₄ reacts with 500 ml 0.1 molar NaOH.Density of solution is 1.4g/ml.Calculate molality of left specie.

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200 ml 0.1 molar H 2 SO 4 reacts with 500 ml 0.1 molar NaOH.Density of solution is 1.4g/ml.Calculate molality of left specie.

200 ml 0.1 molar H2SO4 reacts with 500 ml 0.1 molar NaOH.Density of solution is 1.4g/ml.Calculate molality of left specie.

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200 ml 0.1 molar H₂SO₄ reacts with 500 ml 0.1 molar NaOH.Density of solution is 1.4g/ml.Calculate molality of left specie.