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Help me in finding the oxidation number of Fe in Fe3O4
Solution:
In Fe3O4 , each O has o.n = -2 and therefore we have:
4(-2) + 3 (o.n. of Fe ) = 0 or the o.n. of Fe = 8/3
Actually Fe3O4. known as magnetic oxide of iron is a stoichiometric mixture of ferrous (FeO) and ferric (Fe3O4 ) oxides and the value 8/3 for the oxidation number is the average of all the Fe atoms in the molecule.
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