find pressure at which the PV vs P curve acquires minima for 1 mole of oxygen gas at 0°C . a=1.36 L² atm mol&oline;² , b=32 cm³ mol¯¹

Question

find pressure at which the PV vs P curve acquires minima for 1 mole of oxygen gas at 0&deg;C . a=1.36 L&sup2; atm mol&oline;&sup2; , b=32 cm&sup3; mol&macr;&sup1;

Ramesh V · Answer

for n=1, T=273K

the eqn is : PV = Pb + RT + ab/V² - a/V --- (1)

differentiating for minima , d(PV)/dV = 0 whihc gives

0 = -2ab/V³ + a/V²

so V = 2b .. (2)

hence on substituting V,a,b,R,T, and putting (2) in (1)

we get P = RT/b - a/4b²

on substituting values you can easily get value of P

--

regards

Ramesh

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find pressure at which the PV vs P curve acquires minima for 1 mole of oxygen gas at 0°C . a=1.36 L² atm mol‾² , b=32 cm³ mol¯¹

find pressure at which the PV vs P curve acquires minima for 1 mole of oxygen gas at 0°C . a=1.36 L² atm mol‾² , b=32 cm³ mol¯¹

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