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1. Calculate the useful work of the reaction Ag(s) + Cl2(g) AgCl(s) Given EoCl2/Cl– = + 1.36 V EoAgCl/Ag,Cl– = 0.22 V if PCl2 = 1 atm and T = 298 K (a) 110 kJ/mol (b) 220 kJ/mol (c) 55 kJ/mol (d) 1000 kJ/mol

1. Calculate the useful work of the reaction
Ag(s) + Cl2(g) AgCl(s) Given EoCl2/Cl– = + 1.36 V
EoAgCl/Ag,Cl– = 0.22 V
if PCl2 = 1 atm and T = 298 K
 
(a) 110 kJ/mol
 (b) 220 kJ/mol
(c) 55 kJ/mol
(d) 1000 kJ/mol

Grade:12

1 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
6 years ago
Ag + 1/2 Cl2 ===> AgCl
Ag => Ag+ + e- (oxidation half)
1/2 Cl2 + e- => Cl- (reduction half)
E0cell = Ecathod - Eanode = EAgCl/Ag+ - ECl2/Cl-
= 1.36 - 0.22 = 1.14 volts

maximum useful work = nFEocell
n = 1 , F = 96500 so
W = 96500x1.14 = 11001 joules = 110 kJ

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