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Magnetic momentum of an M^=3 ion is (35)^1/2 .
then no. of electrons in d orbital of m element will be ?
351/2 gives 5 unpaired electrons using magnetic moment= (n*(n+2))1/2 and d has 5 orbitals, if in the question it is +3 (typing mistake done by you) charge then the metal should have 8 electrons (=5present+3 lost )in outer cell out of which 2 will be in S orbital so finally d has 6 electrons.
Thanks & Regards
Vikash Kumar,
askIITians Faculty
B.Tech, IIT Delhi
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