Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Determine the molecular formula of an oxide of iron in which the mass per cent
Mass percent of iron (Fe) = 69.9% (Given)Mass percent of oxygen (O) = 30.1% (Given)Number of moles of iron present in the oxide = 1.25Number of moles of oxygen present in the oxide = 1.88Ratio of iron to oxygen in the oxide, = 1 : 1.5= 2 : 3 The empirical formula of the oxide is Fe2O3.Empirical formula mass of Fe2O3 = [2(55.85) + 3(16.00)] gMolar mass of Fe2O3 = 159.69 g
Molecular formula of a compound is obtained by multiplying the empirical formula with n.Thus, the empirical formula of the given oxide is Fe2O3 and n is 1.Hence, the molecular formula of the oxide is Fe2O3.
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !