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Determine the molecular formula of an oxide of iron in which the mass per cent



Determine the molecular formula of an oxide of iron in which the mass per cent


Grade:11

1 Answers

Simran Bhatia
348 Points
7 years ago

Mass percent of iron (Fe) = 69.9% (Given)
Mass percent of oxygen (O) = 30.1% (Given)
Number of moles of iron present in the oxide 
= 1.25
Number of moles of oxygen present in the oxide 
= 1.88
Ratio of iron to oxygen in the oxide,
 
= 1 : 1.5
= 2 : 3
 The empirical formula of the oxide is Fe2O3.
Empirical formula mass of Fe2O3 = [2(55.85) + 3(16.00)] g
Molar mass of Fe2O3 = 159.69 g



Molecular formula of a compound is obtained by multiplying the empirical formula with n.
Thus, the empirical formula of the given oxide is Fe2O3 and n is 1.
Hence, the molecular formula of the oxide is Fe2O3.

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