0

Guest

Courses New

The catalysts decrease the Ea from 100 K J mol^-1 to 80 K J mol^-1 . At what temperature the rate of reaction in the absence of catalyst at 500 K will be equal to rate of reaction in presence of catalyst .

The catalysts decrease the Ea from 100 K J mol^-1 to 80 K J mol^-1 . At what temperature the rate of reaction in the absence of catalyst at 500 K will be equal to rate of reaction in presence of catalyst .

Grade:11

2 Answers

Mujahid Ahmed
42 Points
10 years ago

Apply Arhenius equation.

K = Ae^-Ea/RT

 

If the two Rates are equal. 

e^-Ea1/RT1 = e^-Ea2/RT2

Ea1/T1 = Ea2/T2

 

100/T = 80/500

T = 625 K

 

Approve if i helped.

ashish chauhan
13 Points
5 years ago
the catalyst decreses the Ea from 100 kj mol to 80 kj mol .at what temperature the rate of reaction in absence of catalyst at 500 k will be equal to rate of reaction in presence of catalyst

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More