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Calculate the amount of 92 U 235 which must go nuclear fission to produce the same amount of energy as produced by 1 ton of coal. The heat of combustion of coal is 8X10 3 cal/gram. The fission of 92 U 235 produces 200 Mev energy/fission. (Use 1 cal = 4.2 J, 1 ton = 10 6 gram. AV number is 6.023X10 23 and 1. 602 X 10 -19. J= 1eV)
Hi Kiran, combustion of coal is 8X103 cal/gram 1 ton produces=8X103x106x4.2 J 200 MeV = 200 * 106*1. 602 * 10-19. J/fission let y fissions then y*200 * 106x1. 602 X 10-19.=8X103x106x4.2 y=10.487*1020 atoms no of moles = y/6.023X1023 =0.00174 moles
Hi Kiran,
combustion of coal is 8X103 cal/gram
1 ton produces=8X103x106x4.2 J
200 MeV = 200 * 106*1. 602 * 10-19. J/fission
let y fissions
then y*200 * 106x1. 602 X 10-19.=8X103x106x4.2
y=10.487*1020 atoms
no of moles = y/6.023X1023
=0.00174 moles
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