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Calculate the amount of 92U235 which must go nuclear fission to produce the same amount of energy as produced by 1 ton of coal. The heat of combustion of coal is 8X103 cal/gram. The fission of 92U235 produces 200 Mev energy/fission. (Use 1 cal = 4.2 J, 1 ton = 106gram. AV number is 6.023X1023 and 1. 602 X 10-19. J= 1eV)

J Ravi Kiran , 15 Years ago
Grade 11
anser 1 Answers
askiitian.expert- chandra sekhar

Last Activity: 15 Years ago

Hi Kiran,

combustion of coal is 8X103 cal/gram

1 ton produces=8X103x106x4.2 J

200 MeV = 200 * 106*1. 602 * 10-19.  J/fission

let y fissions

then y*200 * 106x1. 602 X 10-19.=8X103x106x4.2

       y=10.487*1020 atoms

no of moles = y/6.023X1023

                       =0.00174 moles

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