a gas occupies 0.6 litres under a pressure of 0.92 bar. under what pressure will the volume of gas be reduced by 20% of its original volume ? ( temp is constant)

Question

Naveen Gunturu · Answer

is the answer 4.6?

anurag singhal · Answer

at a constant temperature P is infersely proportionsl to 1/V PV=comstant at same temperature apply P 1 V 1 = P 2 V 2 thus u will get P as 1.15 bar

trishit thakur · Answer

P 1 V 1 =P 2 V 2 .92*.6= .12*P 2 P 2= 4.6 bar :answer

askiitian.expert- chandra sekhar · Answer

Hi Tejas, V1=0.6 lit V2=V1-V1*20/100 = V1(1-20/100)=V1(80/100) P1=0.92 bar Boyle's law: P1*V1=P2*V2 0.92*V1=P2*V1*0.8 P2=0.92/0.8=1.15 bar

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a gas occupies 0.6 litres under a pressure of 0.92 bar. under what pressure will the volume of gas be reduced by 20% of its original volume ? ( temp is constant)

a gas occupies 0.6 litres under a pressure of 0.92 bar. under what pressure will the volume of gas be reduced by 20% of its original volume ? ( temp is constant)

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