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Calculate the velocity of an electron placed in the 2nd orbit of the Li2+ ion,. Also calculate the no. of revolutions per second that it makes around the nucleus.
The velocity of an electorn in nth shell of the hydrogen like atom is ((2.18*10^6)*Z)/n. Putting Z=3(atomic no of lithium) and n=2,
=(2.18*10^6)*3/2
=(3.27*10^6)ms-1.
No of revolution per second 2(pi)r/v where r=(0.529*(n^2))/Z)*10-10
r=2(pi)((0.529*n^2)/Z)*10-10
r=2(pi)((0.529*4)/3)*10-10=(4.42*10-10)m
Time=(4.42*10-10)m/(3.27*10^6)ms-1=1.35*10-16
No of revolutions is 1/T=.74*1016
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