A first order rkn at 298K can be expressed by generalisation logK(ln s-1)=17.64-(2.5*104/T) then what is the activation energy of the rkn will be [K=rate constant of rkn ;T=Kelvin temp.] ?
A first order rkn at 298K can be expressed by generalisation logK(ln s-1)=17.64-(2.5*104/T) then what is the activation energy of the rkn will be [K=rate constant of rkn ;T=Kelvin temp.] ?










