CALCULATE THE MOLARITY OF 30 GM OF CO[NO3]2.6H2O IN 4.3 L OF SOLUTION
sai sushma , 14 Years ago
Grade
Physical Chemistry> SOLUTIONS...
2 Answers
Gurwinder Kaur
Mass of CO[NO3]2.6H2O = 30gm
Volume of solution = 4.3L
Molar mass of CO[NO3]2.6H2O = 291 g/mol
no. of moles of solute = 30/291 mol
Molarity of solution = no. of moles of CO[NO3]2.6H2O/ Volume of sol. in litres
= 30/(291*4.3)
= 0.0239 molar
plz approve if it is helpful...........
Joseph Ogar
n = CV
n = no. of moles = mass/molar mass
Therefore n = 30/291
V = Volume in L = 4.3 L
C = Concentration in mol dm-3 or Molarity
= n/V = (30/291)/4.3
= 0.0239 M
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