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the number of moles of Cr2O72- needed to oxidize 0.136 equivalents of N2H5+ by the reaction N2H5+Cr2O72- ? N2+Cr3+ +H2O is (a) 0.136 (b) 0.272 (c) 0.816 (d) 0.0227

the number of moles of Cr2O72- needed to oxidize 0.136 equivalents of N2H5+ by the reaction N2H5+Cr2O72- ? N2+Cr3+ +H2O is

(a) 0.136

(b) 0.272

(c) 0.816

(d) 0.0227


Grade:12

2 Answers

SAGAR SINGH - IIT DELHI
878 Points
13 years ago

Dear student,

Use the concept of equivalents...

equivalent weight=molecular weight/ n factor

moles=mass/molecular mass

 

Arnab Maji
33 Points
5 years ago
.136 equivalent N2H5 + = .136 equivalent dichromate
                                          =.136/6 mole dichromate
                                           =.0227 mole dichromate
    So answer is .0227 mole

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