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The dissociation energy of H2 is 430.53 KJ/mol. If H2 is exposed to radiant energy of wavelength 253.7 nm, what % of radiant energy will be converted into K.E.
Dear student,
dissociation energy is 430.53 KJ/mol
photoon energy=hc/wavelength
Now calculate the radiant energy.....
bond dissociation energy = 430.53kj/mol = 430.53*103j/mol
this energy is for 1 mol so for 1 molecule
E = 430.5*103/Na (Na is avagadro number)
E = 7.2*10-19joule
energy of radiation = hc/lamda = 7.8*10-19joules
here h is planks constant , c is speed of light , lamda is wavelength)
energy given through radiation is more than dissotion so excess energy
will come in form of KE of dissociated atoms ...
dE = axcess energy = (7.8-7.2)*10-19 = 0.6*10-19
(dE/E)*100 = 8%
so 7.8% of energy is converted to KE...
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