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Grade:

                        

A single electron orbits around a stationary nucleus of charge +Ze where Z is atomic no. and e is the magnitude of the electric charge. The hydrogen like species required 47.2 eV to excite the electron from the second bohr orbit to the third bohr orbit. Find the value of Z.

9 years ago

Answers : (2)

vikas askiitian expert
509 Points
							

E = 13.6[1/n12-1/n22]Z2

this is the energy required to exite a electron from lower orbit to higher

when electron jumps from n = 2 to n = 3 then

E = 13.6[1/4-1/9]Z2

 

E = 47.2            (given) so

47.2 = 13.6[1/4-1/9]Z2

Z2 = 25

Z = 5

9 years ago
SAGAR SINGH - IIT DELHI
879 Points
							

Dear student,

Use

E=-13.6Z2/n2=-47.2

9 years ago
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