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A single electron orbits around a stationary nucleus of charge +Ze where Z is atomic no. and e is the magnitude of the electric charge. The hydrogen like species required 47.2 eV to excite the electron from the second bohr orbit to the third bohr orbit. Find the value of Z.

pranshu aggarwal , 15 Years ago
Grade
anser 2 Answers
vikas askiitian expert

E = 13.6[1/n12-1/n22]Z2

this is the energy required to exite a electron from lower orbit to higher

when electron jumps from n = 2 to n = 3 then

E = 13.6[1/4-1/9]Z2

 

E = 47.2            (given) so

47.2 = 13.6[1/4-1/9]Z2

Z2 = 25

Z = 5

ApprovedApproved
Last Activity: 15 Years ago
SAGAR SINGH - IIT DELHI

Dear student,

Use

E=-13.6Z2/n2=-47.2

Last Activity: 15 Years ago
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