Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A single electron orbits around a stationary nucleus of charge +Ze where Z is atomic no. and e is the magnitude of the electric charge. The hydrogen like species required 47.2 eV to excite the electron from the second bohr orbit to the third bohr orbit. Find the value of Z.


A single electron orbits around a stationary nucleus of charge +Ze where Z is atomic no. and e is the magnitude of the electric charge. The hydrogen like species required 47.2 eV to excite the electron from the second bohr orbit to the third bohr orbit. Find the value of Z.


Grade:

2 Answers

vikas askiitian expert
509 Points
10 years ago

E = 13.6[1/n12-1/n22]Z2

this is the energy required to exite a electron from lower orbit to higher

when electron jumps from n = 2 to n = 3 then

E = 13.6[1/4-1/9]Z2

 

E = 47.2            (given) so

47.2 = 13.6[1/4-1/9]Z2

Z2 = 25

Z = 5

SAGAR SINGH - IIT DELHI
879 Points
10 years ago

Dear student,

Use

E=-13.6Z2/n2=-47.2

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free