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number of valence electrons are 5 ...
3 electrons take part in bonding so 2 are remaining ..
lone paires = 1
bond paires = 3 (total number of bonds)
1. First know the electronic configuration of N and H
2. We know Nitrogen has 5 valance electrons and H has 1 valance electron.
in NH3 , 3 of the 5 valance electrons on N are taken by 'H' , so it has 2 electrons left.
3. These 2 electrons will prevent it from acquiring a trigonal planar shape as they will repel the bonding.
we know this because , according to VSEPR theory , the bonds should be in such a position such that the repulsions between them is very less.
so NH3 gets a tetrahedral shape, with a lone pair of electrons.
so the final sctructure will look like ..
Please approve !
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