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When 1-pentyne (A) is treated with 4N alcoholic KOH at 175°C, it is converted slowly into an equillibrium mixture of 1.3% 1-pentyne (A), 9.5% 2-pentyne (B) and 3.5% of 1.2-pentadiene (C) .The equillibrium was maintained at 175°C. Calculate ΔG° for the following eqilibria. B ↔ A, ΔG°1=?? B ↔ C, ΔG°2=?? From the calculated value of ΔG°1 & ΔG°2 indicate the order of stabiity of (A), (B), & (C). Write a reasonable reaction mechanism showing al intermediates leading to (A), (B) & (C).

When 1-pentyne (A) is treated with 4N alcoholic KOH at 175°C, it is converted slowly into an equillibrium mixture of 1.3%        1-pentyne (A), 9.5% 2-pentyne (B) and 3.5% of 1.2-pentadiene (C) .The equillibrium was maintained at 175°C. Calculate ΔG° for the following eqilibria.


B ↔ A,      ΔG°1=??


B ↔ C,      ΔG°2=??


From the calculated value of  ΔG°1 &  ΔG°2 indicate the order of stabiity of (A), (B), & (C). Write a reasonable reaction mechanism showing al intermediates leading to (A), (B) & (C).

Grade:12

2 Answers

SAGAR SINGH - IIT DELHI
879 Points
10 years ago

Dear student,

Gibbs Free Energy (G) - The energy associated with a chemical reaction that can be used to do work.  The free energy of a system is the sum of its enthalpy (H) plus the product of the temperature (Kelvin) and the entropy (S) of the system:

Free energy of reaction (G)

  • The change in the enthalpy (H) of the system minus the product of the temperature (Kelvin) and the change in the entropy (S) of the system:

Standard-state free energy of reaction (G)

  • The free energy of reaction at standard state conditions:

 

Standard-state conditions

  • The partial pressures of any gases involved in the reaction is 0.1 MPa.
  • The concentrations of all aqueous solutions are 1 M.

Measurements are also generally taken at a temperature of 25C (298 K)

 

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Sagar Singh

B.Tech, IIT Delhi

Aiswarya Ram Gupta
35 Points
10 years ago

thnku

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