Sudheesh Singanamalla
Last Activity: 14 Years ago
n-factor is defined as the total change in oxidation number per mole of the substance .
take an example :
CuCN -----------> Cu+2 + CO2 + HNO3
(A) 11
(B) 7
(C) 9
(D) 3
Here , Cu+ is converted to Cu2+ .
There is no change in oxidation number for C ( it remains as +4 )
N is converted from -5 to +5 state .
So the net change in oxidation number , n-factor = (2-1) + [5-(-5)]
=11 .
So Answer is (A.)
so now try solving this question.
calculate n factor of HCuCl2 in
2HCuCl2 → Cu + Cu2+ + 4Cl-+ 2H+
Hope that helps , Please approve