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if the K.E of electron is Increased by 4 times then Broglie wavelength associated with it would become????????
de broglie wavelength (lamda)L= h/(2mKE)1/2 ..............1
here h is planks constant, m is mass of electron & KE is kinetic energy...
from eq 1
L(lamda) is inversly proportional to (KE)1/2
L/L1 = {(KE)f /(KE)i}1/2
(KE)f = 4(KE)i (given)
so L/L1 = 2 or
L1 = L/2
it means de broglie wavelength of electron is decreased to half times the initial value....
According to De BROGLIE,
wavelength=h/root 2Em
where h....Planck constant
E.... Kinetic energy, m= mass of electron
Thus, when kinetic energy associated with electron is increased four times, then wave length would become half of the initial value.
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