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# if the K.E of electron is Increased by 4 times then Broglie wavelength associated with it would become????????

509 Points
10 years ago

de broglie wavelength (lamda)L=  h/(2mKE)1/2                 ..............1

here h is planks constant, m is mass of electron  & KE is kinetic energy...

from eq 1

L(lamda) is inversly proportional to (KE)1/2

L/L1   =   {(KE)f /(KE)i}1/2

(KE)f = 4(KE)i   (given)

so    L/L1 = 2   or

L1 = L/2

it means de broglie wavelength of electron is decreased to half times the  initial value....

PRASHANT MISHRA
4 Points
10 years ago

According to De BROGLIE,

wavelength=h/root 2Em

where h....Planck constant

E.... Kinetic energy, m= mass of electron

Thus, when kinetic energy associated with electron is increased four times, then wave length would become half of the initial value.