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1 mole of MnO4- oxidises x moles of Ferric oxalate value of X is--
Dear student PLease state the medium I am teling you in acidic medium 3 MnO4{-} + 24 H{+} + 5 FeC2O4 → 3 Mn{2+} + 12 H2O + 10 CO2 + 5 Fe{3+} (1 mol FeC2O4) x (3 mol MnO4{-} / 5 mol FeC2O4) = 0.6 mol MnO4{-} hence0.6 mol MnO4{-} = 1 mole ferric oxalate hence1 mol MnO4{-} = 1 / 0.6 = 10/6 = 1.66 mole os ferric oxalate
as u r not mention the medium hence the que is wrong’we cant stse an aswer unless mention the medium so plz mention the medium which u r reactin the reagents
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