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Grade 12Physical Chemistry

1 mole BaF2 +2 mole H2SO4 gives rise to resulting mixture it will be neutralized by -
a) 1 mol of KOH
b) 2 mol of H2SO4
c) 4 mol KOH
d) 2 mol of KOH

Ayush Mittal

7 Years agoGrade 12

4 Answers

Arun

7 Years ago

The base OH- exactly neutralises mole of H+ion, for example 1 mol of OH- will neutralise 1 mol of H+ ion.

So as per questionnaire 2 moles of H+ ion from H2SO4 will reacts with 2 moles of OH- for neutralisation.

Hence answer is Option D) 2 moles KOH.

I am not sure about my answer

Ayush Mittal

7 Years ago

It is a multiple correct question.The answer given is option B and option C. Please think about it again. It would be much grateful.

Regards

Thagaval medai

7 Years ago

BaF2 +H2SO4=BaSO4+2HF

(BaSO4+2HF)+X=products (neutralization)

Mole*n factor=equivalence

BaSO4:-

1*2=2

2HF:-

2*1=2

Equivalence(BaSO4+2HF)=Equivalence (X)(neutralization rxn)

2+2=moles*n factor of X

1)KOH

4=n*1

n=4(no.of moles)

Hence 4KOH

2)Ca(OH)2

4=n*2

n=2(no.of moles)

Hence 2Ca(OH)2

Thus 4 KOH & 2Ca(OH)2

B

7 Years ago

BaF₂+ H₂SO₄= BaSO₄+ 2HF

1 mol each of the above reactants are consumed

and 2 moles of HF is formed.

Now the mixture has 1 mol of H₂SO₄ and 2 moles

of HF.

For neutralisation 4 moles of OH^- will be required.

Hence, B (which should be 2 moles of Ca(OH)₂)

and C will be the right answer.

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