1 mole BaF2 +2 mole H2SO4 gives rise to resulting mixture it will be neutralized by -
a) 1 mol of KOH
b) 2 mol of H2SO4
c) 4 mol KOH
d) 2 mol of KOH

Question

1 mole BaF2 +2 mole H2SO4 gives rise to resulting mixture it will be neutralized by - a) 1 mol of KOH b) 2 mol of H2SO4 c) 4 mol KOH d) 2 mol of KOH

Arun · Answer

The base OH - exactly neutralises mole of H + ion, for example 1 mol of OH - will neutralise 1 mol of H + ion. So as per questionnaire 2 moles of H + ion from H 2 SO 4 will reacts with 2 moles of OH - for neutralisation. Hence answer is Option D) 2 moles KOH. I am not sure about my answer

Ayush Mittal · Answer

It is a multiple correct question.The answer given is option B and option C. Please think about it again. It would be much grateful. Regards

Thagaval medai · Answer

BaF2 +H2SO4=BaSO4+2HF (BaSO4+2HF)+X=products (neutralization) Mole*n factor=equivalence BaSO4:- 1*2=2 2HF:- 2*1=2 Equivalence(BaSO4+2HF)=Equivalence (X)(neutralization rxn) 2+2=moles*n factor of X 1)KOH 4=n*1 n=4(no.of moles) Hence 4KOH 2)Ca(OH)2 4=n*2 n=2(no.of moles) Hence 2Ca(OH)2 Thus 4 KOH & 2Ca(OH)2

B · Answer

BaF 2 + H 2 SO 4 = BaSO 4 + 2HF 1 mol each of the above reactants are consumed and 2 moles of HF is formed. Now the mixture has 1 mol of H 2 SO 4 and 2 moles of HF. For neutralisation 4 moles of OH - will be required. Hence, B (which should be 2 moles of Ca(OH) 2 ) and C will be the right answer.

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1 mole BaF2 +2 mole H2SO4 gives rise to resulting mixture it will be neutralized by - a) 1 mol of KOH b) 2 mol of H2SO4 c) 4 mol KOH d) 2 mol of KOH

1 mole BaF2 +2 mole H2SO4 gives rise to resulting mixture it will be neutralized by -
a) 1 mol of KOH
b) 2 mol of H2SO4
c) 4 mol KOH
d) 2 mol of KOH

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1 mole BaF2 +2 mole H2SO4 gives rise to resulting mixture it will be neutralized by - a) 1 mol of KOH b) 2 mol of H2SO4 c) 4 mol KOH d) 2 mol of KOH

1 mole BaF2 +2 mole H2SO4 gives rise to resulting mixture it will be neutralized by -a) 1 mol of KOHb) 2 mol of H2SO4c) 4 mol KOHd) 2 mol of KOH

4 Answers

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1 mole BaF2 +2 mole H2SO4 gives rise to resulting mixture it will be neutralized by -
a) 1 mol of KOH
b) 2 mol of H2SO4
c) 4 mol KOH
d) 2 mol of KOH