0

Guest

Courses New

1.12ml of a gas is produced at STP by the action of alcohol ROH with CH3MgI .The molecular mass of alcohol is?

1.12ml of a gas is produced at STP by the action of alcohol ROH with CH3MgI .The molecular mass of alcohol is?

Grade:11

3 Answers

Bhavya
askIITians Faculty 1281 Points
7 years ago
Dear student
ROH + CH3MgI ----> R-CH3 + MgI(OH)
Here we need to compare moles of ROH and R-CH3 but here question is incomplete since we are not given the weight of ROH taken.
Amaan
19 Points
5 years ago
1.12 mL is obtained from 4.12 mg
22400 mL will be obtained from
Apurv
15 Points
5 years ago
ROH + CH3MgI→CH4 + RO−MgI+Volume of gas produced = 112 mLMass of alcohol used = 412 mg1 mole of alcohol produce 1 mole of CH4.So, 22.4 L CH4 will be produced by the molecular weight of alcohol.112 mL CH4 is produced from 412 mg of alcoholSo, 22400 mL of CH4 will be produced by = 412112×22400=82400 mg of alcohol = 82.4 g of ROHSo, 
 

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More