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What will be the oxidation number of Ni in. K 2 [Ni(CN) 4 ]?

What will be the oxidation number of Ni in.  K2[Ni(CN)4]?

Grade:11

3 Answers

Arun
25750 Points
5 years ago

In the compound K2(Ni(CN)4), the anion has a charge of -2, because the compounds contains 2 K+ ions, and thus the charge of the anion should balance out the charge of the cations.

We know that CN has a charge of -1. Therefore we can find the oxidation number of Ni through simple calculation.

If we allow the charge of Ni to be x, then:

x + 4(-1)= -2

x = +2

Therefore the oxidation number of Ni in K2(Ni(CN)4) is +2.

bhavana
34 Points
5 years ago
It is +2 
Since the over all charge on complex part is -2 
Therefore -2=x+(-1*4)
So x (charge of Ni is +2
na batau
17 Points
5 years ago
 

In the compound K2(Ni(CN)4), the anion has a charge of -2, because the compounds contains 2 K+ ions, and thus the charge of the anion should balance out the charge of the cations.

We know that CN has a charge of -1. Therefore we can find the oxidation number of Ni through simple calculation.

If we allow the charge of Ni to be x, then:

x + 4(-1)= -2

x = +2

Therefore the oxidation number of Ni in K2(Ni(CN)4) is +2.

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