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What will be the oxidation number of Ni in. K2[Ni(CN)4]?
In the compound K2(Ni(CN)4), the anion has a charge of -2, because the compounds contains 2 K+ ions, and thus the charge of the anion should balance out the charge of the cations.We know that CN has a charge of -1. Therefore we can find the oxidation number of Ni through simple calculation.If we allow the charge of Ni to be x, then:x + 4(-1)= -2x = +2Therefore the oxidation number of Ni in K2(Ni(CN)4) is +2.
In the compound K2(Ni(CN)4), the anion has a charge of -2, because the compounds contains 2 K+ ions, and thus the charge of the anion should balance out the charge of the cations.
We know that CN has a charge of -1. Therefore we can find the oxidation number of Ni through simple calculation.
If we allow the charge of Ni to be x, then:
x + 4(-1)= -2
x = +2
Therefore the oxidation number of Ni in K2(Ni(CN)4) is +2.
It is +2 Since the over all charge on complex part is -2 Therefore -2=x+(-1*4)So x (charge of Ni is +2
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