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Total No. of stereo isomers formulais 2^n. But the formulas like 2^(n.-1)+2^(n/2-1) not giving same result. Let us calculate for an unsymmetrical molecule with 4 Chiral carbons. Total stereo isomers=2^4=16 Using another formula 2^(4-1)+2^(4/2-1)=10 for a unsymmetrical molecule with 5 assymmetric carbon Total 2^5=32 and another way rsulting 2^4=16. how my perception is wrong?

Total No. of stereo isomers formulais 2^n. But the formulas like 2^(n.-1)+2^(n/2-1) not giving same result. Let us  calculate for an unsymmetrical molecule with 4 Chiral carbons. 
Total stereo isomers=2^4=16
Using another formula 2^(4-1)+2^(4/2-1)=10
for a unsymmetrical molecule with 5 assymmetric carbon
Total 2^5=32 and another way rsulting 2^4=16. how my perception is wrong?  

Grade:12

1 Answers

Ravleen Kaur
askIITians Faculty 1452 Points
5 years ago
Pease go through our revision notes

https://www.askiitians.com/iit-jee-isomerism/enantiomers-diastereomers-meso-compounds/

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