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The volume of 0.25M of H3PO3 required to neutralize 25ml of 0.03M Ca(oh) 2

The volume of 0.25M of H3PO3 required to neutralize 25ml of 0.03M Ca(oh) 2

Grade:12

1 Answers

Mahima Kanawat
1010 Points
5 years ago
Dear student
For neutralization equivalents of both solutions must be i. e., N1V1=N2V2
0.25*2*V=0.03*2*25
V = 3 ml
WITH REGARDS 
MAHIMA 
ASKIITIANS FORUM EXPERT 
 

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