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The number of isomers for the compound with molecular formula C2BrClFl is : (a) 3 (b) 4 (c) 5 (d) 6

The number of isomers for the compound with molecular formula C2BrClFl is :

(a) 3

(b) 4

(c) 5

(d) 6

Grade:12th pass

3 Answers

Naveen Kumar
askIITians Faculty 60 Points
8 years ago
There will be 6 isomers possible for this formula.
take two halogens on any one of doubly bonded carbon and u would have three possible combination.
For each of this three structure each one will have cis and trans structures and so total 6.
RaJa Kumar
26 Points
5 years ago
My opinion goes to 6 isomer only for this.... We can add only 3 isomer but here is the matter of cis trans so total structural and geometrical isomer will be 6 only
Rishi Sharma
askIITians Faculty 646 Points
2 years ago
Dear Student,
Please find below the solution to your problem.

There will be 6 isomers possible for this formula. take two halogens on any one of doubly bonded carbon and u would have three possible combination. For each of this three structure each one will have cis and trans structures and so total 6.

Thanks and Regards

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