The number of isomers for the compound with molecular formula C2BrClFl is :

(a) 3

(b) 4

(c) 5

(d) 6

There will be 6 isomers possible for this formula.
take two halogens on any one of doubly bonded carbon and u would have three possible combination.
For each of this three structure each one will have cis and trans structures and so total 6.

My opinion goes to 6 isomer only for this.... We can add only 3 isomer but here is the matter of cis trans so total structural and geometrical isomer will be 6 only

Dear Student,
Please find below the solution to your problem.

There will be 6 isomers possible for this formula. take two halogens on any one of doubly bonded carbon and u would have three possible combination. For each of this three structure each one will have cis and trans structures and so total 6.

Thanks and Regards