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the % by volume of C4H10 in a gaseous mixture of C4H10,CH4 and CO is 40 .when 200 ml in the mixture is burnt in excess of O2 . find volume ( in ML) of CO2 produced
40% of total volume = 120 ml of 200 ml.Balanced eqn. for each compound, CH4 + 2O2 ----------> CO2 + 2H2O V ml V ml CO + ½ O2 -------> CO2 (120 – V) ml (120 – V) ml C4H10 + 13/2 O2 -----------> 4CO2 + 5 H2O120 ml v/4 v = 480 ml. Hence total volume of CO2 => 480 ml + V + 120 – V => 600 ml.
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